1.How many male are only great?
- 17
- 8
- 24
- 12
According to the given information:
We can see that the shaded part denotes the number of males that are only great = 8 + 4 = 12.
That is given as “12”.
Hence, the correct answer is “12”.
Mistake Points We can see that the shaded part denotes the number of males that are only great = 8 + 4 = 12.
Here Only great means male cannot be Human. So, the common part of great and man will be the correct answer(which is not human).
16 would not add because 16 belongs to human.
Hence, the correct answer is “12”.
2.Solve using BODMAS rule:
34 + 16 ÷ 2 × 3 + 5 ÷ 15 × 9 – 6 + 8- 69
- 63
- 66
- 71
Given expression: 34 + 16 ÷ 2 × 3 + 5 ÷ 15 × 9 – 6 + 8
= 34 + 8 × 3 + 1/3 × 9 – 6 + 8
= 34 + 24 + 3 – 6 + 8
= 69 – 6
= 63
Hence, the correct answer is 63.
- A and B
- C and F
- A and C
- E and F
Six Persons : A, B, C, D, E and F
i) C is sitting second to the left of F.
ii) A is an immediate neighbor of D and C.
iii) E sits to the left of A but B sits to the right of A.
Hence, E and F are sitting at the extreme ends.
4.Directions: The question below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read both the statements and give answer.
What is the distance between A and B?
Statement I: C is in midway of distance between A and D.
Statement II: B is 3 km east of E.- I alone is sufficient while II alone is not sufficient.
- II alone is sufficient while I alone is not sufficient.
- Both I and II are sufficient.
- Neither I nor II is sufficient.
1) Distance between A and D is not specified. So, finding its midway and placing C is not possible. So, statement I alone is not sufficient to answer the question.
2) B is 3 km east of E.
So, statement II alone is not sufficient to answer the question.
3) Combination of statements I and II is not possible.
Hence, the data given in the both statements I and II together are not sufficient to answer the question.
5.In a certain code ‘FLOOR’ can be written as ‘128773’ and ‘FRANK’ can be written as ‘123294’. How is ‘LOFAR’ written in that code?
- 871123
- 871223
- 861223
- 871220
The codes have been assigned as follows,
FLOOR →
F | L | O | O | R |
12 | 8 | 7 | 7 | 3 |
FRANK →
F | R | A | N | K |
12 | 3 | 2 | 9 | 4 |
Similarly,
LOFAR →
L | O | F | A | R |
8 | 7 | 12 | 2 | 3 |
Hence, LOFAR is coded as 871223.
6.Which answer figure will complete the pattern in the following question figure?
- 1.
- 2.
- 3.
- 4.
The options which completes the given figure is option 2):
Hence, option 2) is the correct answer.
- Saturday
- Sunday
- Monday
- Tuesday
1996 is a leap year and so it has 2 odd days.
However, the period under consideration is from 26th March 1997 to 26th March 1996.
Hence, the same date between the two years does not include Feb 29, and hence has only one odd day.
Hence, day on 26th March, 1996 = Monday − 1 = Sunday
Hence, option 2.
8.Direction: In the question below are given two statements followed by two conclusions numbered I and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.
Statements:
I. All bottle is plastic
II. Some bags are plastic
Conclusions:
I. Some bags are not bottle
II. Some plastic are not bags- Only conclusion I follows
- Only conclusion II follows
- None follows
- All Follows
Concept:
1) We have to check the conclusions are 100% match with the statement. If the conclusion is 100% match with the given statement then the conclusion is true. If there is a 1% chance of not following the statement then the conclusion is considered to be false.
2) The possibility case can be considered to be “false” in “definite case”.
3) In Possibility case, either “can” or “possible” word must be present.
The least possible Venn diagram for the given statements is as follows:
Conclusions:
I. Some bags are not bottle → False (There is no direct relation given between bottle and bags so it can be possible but not definite, hence, false)
II. Some plastic are not bags → False (As “Some bags are plastic” given so some plastic can be bags it can be possible but some plastic are not bags it is not definite, hence, false)
Hence, the correct answer is “None follows”.
Additional Information
Note: The answer here will not be “Neither conclusion I nor II follows”.
Don’t get confused as in the “neither-nor case” the subject and predicate in both the conclusions must be the same.
9.Find the missing character in the following figure.
- 125
- 215
- 251
- 512
Correct Answers Is: 1
10.A bag contains 50p, 25p and 10p coins in the ratio 12 : 8 : 13 amounting to Rs. 186. Find the number of coins of each type.
- 120, 180, 130
- 480, 320, 520
- 260, 160, 240
- 240, 160, 260
Let x be the common multiple.
The ratio of the number of coins of each type = 12 : 8 : 13
So, the number of 50p coins is 12x, the number of 25p coins is 8x and the number of 10p coins is 13x.
According to the question:
(0.50 × 12x + 0.25 × 8x + 0.10 × 13x) = 186 (Here paise is converted to rupees because the total amount is given in terms of rupees)
(6x + 2x + 1.3x) = 186
9.3x = 186
x = 20
Number of 50p coins = 12x = 12 × 20 = 240
Number of 25p coins = 8x = 8 × 20 = 160
Number of 10p coins = 13x = 13 × 20 = 260
Hence, “240, 160, 260” is the correct answer.
12.What will come in the place of the question mark (?) in the following number series?
- 1.
- 2.
- 3.
- 4.
The pattern is-
The elements in the next box are obtained by continuing the alphabetical order to the previous elements in the box.
Hence, option 3 is the correct answer.
13.Select the number from among the given options that can replace the question mark (?) in the following series.
65, 70, 80, 80, 110, 100, ?
- 161
- 145
- 130
- 155
The pattern followed here is:
Hence, ‘155’ is the correct answer.
- 700, 1015, 715
- 810, 1100, 520
- 605, 810, 1015
- none of these
According to the question:
A : B : C = 3 : 4 : 5
if their shares are diminished by Rs. 5, Rs. 10, and Rs. 15 respectively then the amount = 2430 – 5 – 10 -15 = 2400
so their actual shares,
A’s share = 3/12 × 2400 + 5 = 605
B’s share = 4/12 × 2400 + 10 = 810
C’s share = 5/12 × 2400 + 15 = 1015
So, option 3 is the correct answer.
15.Direction: Study the following information carefully to answer the questions given below-
Six persons G, W, L, K, V and B are sitting around a circular table facing outside the center not necessarily in the same order. G sits third right of K. Two persons are sitting between L and B. B sits second right of K. W is not an immediate neighbour of G.
How many persons are sitting between W and V?
- Three
- No one
- One
- Two
According to the given information,
1) Two persons are sitting between L and B.
2) B sits second right of K.
3) G sits third right of K.
4) W is not an immediate neighbour of G.
Hence, two persons are sitting between W and V.
16.Which one of the mirror images of the following combination is correct when the mirror is place at ‘PQ’?
The correct mirror image of the given figure when the mirror is held at the right side is:
Hence, “option (2)” is the correct answer.
- Brother-in-law
- Father
- Husband
- Son-in-law
Preparing the family tree using the following symbol:
Important Points
- L’s only niece V means V is the only niece of L.
The family tree as per the given data:
Here, L is the husband of N.
Hence, the correct answer is “Husband”.
18.J, K L, M, N and O are six teachers. Each one teaches a different subject out of Hindi, English, Math, Science, Social Science and Arts, not necessarily in the same order. Each of them teaches on only one day, from Monday to Saturday, not necessarily in the same order. J teaches Arts on Saturday. L teaches neither English nor Social Science, but he teaches on Thursday. Wednesday is reserved for Maths taught by K. O teaches Science a day before N. Social Science is taught a day before Arts. Which subject is taught by N?
- Arts
- Hindi
- English
- Science
. J, K L, M, N and O are six teachers. Each one teaches a different subject out of Hindi, English, Math, Science, Social Science and Arts, not necessarily in the same order.
2. Each of them teaches on only one day, from Monday to Saturday, not necessarily in the same order.
3. J teaches Arts on Saturday.
4. L teaches neither English nor Social Science, but he teaches on Thursday.
5. Wednesday is reserved for Maths taught by K.
6. O teaches Science a day before N.
7. Social Science is taught a day before Arts.
Day | Teacher | Subject |
Monday | O | Science |
Tuesday | N | |
Wednesday | K | Maths |
Thursday | L |
|
Friday | Social Science | |
Saturday | J | Arts |
As, ‘M’ is left, it will occupy the only vacant space in teachers column.
English and Hindi are left to be placed, but English can’t be placed in the row of Thursday, so the only position left for English is in the row of Tuesday and Hindi will be placed in L’s row.
So, the final arrangement is:
Day | Teacher | Subject |
Monday | O | Science |
Tuesday | N | English |
Wednesday | K | Maths |
Thursday | L | Hindi |
Friday | M | Social Science |
Saturday | J | Arts |
Hence, ‘English’ is taught by N.
19.Directions: Study the following information carefully and answer the questions based on it.
Eight persons: A, B, C, D, E, F, G and H are sitting around a circular table having equal distance between the adjacent persons.
A is sitting opposite to B, who is sitting immediate right to F. F is sitting third to the left of C, who is sitting opposite to E.G is sitting second to the left of H but is not the neighbour of A. (Note: All are facing inside.)
Who is sitting immediate right to D?
- H
- A
- E
- F
Given: Eight persons: A, B, C, D, E, F, G and H are sitting on a circular table having equal distance between the adjacent persons. All are facing towards the centre.
1. A is sitting opposite to B, who is sitting immediate right to F.
2. F is sitting third to the left of C, who is sitting opposite to E.
3. G is sitting second to the left of H but is not the neighbour of A.
Hence, E is sitting immediate right to D.
20.Find the number of parallelograms in the following figure:
- 12
- 15
- 14
- 16
The logic that follows here is:
Therefore, there are 15 parallelograms are present in this figure.
Hence, the correct answer is 15.